I am trying to scrape Name, Location, experience etc from Linkedin.
I have searched specific people on linkedin using google search. I have to go to each link in google results and copy paste the information i need.
I am using XpathOnUrl for this purpose but I am getting empty cell instead of results, although i am able to scrape linkedin profile links from google search results.
Google search page url is: https://www.google.com.pk/search?q=marketing+manager+"ge+healthcare"+“Current.”+site:linkedin.com/in/+-uk+-sg&biw=1366&bih=362&noj=1&ei=BYsDV4vYEoe90gSLkoegBQ&start=440&sa=N
I used code =Dump(XPathOnUrl(https://www.google.com.pk/search?q=marketing+manager+%22ge+healthcare%22+%E2%80%9CCurrent.%E2%80%9D+site:linkedin.com/in/+-uk+-sg&biw=1366&bih=362&noj=1&ei=BYsDV4vYEoe90gSLkoegBQ&start=440&sa=N,"//h3[@class='r']/a","href"))
It worked and returned 10 linkedin profile links which is what i needed.
Now i want to further use XpathOnUrl on each of this linkedin url to go and scrape Name, Location, Experience.
For scraping name i am using code: =XPathOnUrl( linkedin_url , "//*[@id='name']/h1/span/span")
It returns empty cell. No error just empty cell. I have also tried changing @id='name' with @class='name' but no success.
Help in this regard is much appriciated.
@nielsbosma
Thanks